Dates of Week for remaining current year - Run as "bash sed_date_checker.bsh"

#!/bin/bash
# function weekof()
weekof()
{
    local week=$1 year=$2
    local week_num_of_Mon_1 week_day_of_Mon_1
    local first_Mon
    local date_fmt="+%a %b %d %Y"
    local mon sun

    week_num_of_Mon_1=$(date -d $year-01-01 +%W)
    week_day_of_Mon_1=$(date -d $year-01-01 +%u)

    if ((week_num_of_Mon_1)); then
        first_Mon=$year-01-01
    else
        first_Mon=$year-01-$((01 + (7 - week_day_of_Mon_1 + 1) ))
    fi

    mon=$(date -d "$first_Mon +$((week - 1)) week" "$date_fmt")
    sun=$(date -d "$first_Mon +$((week - 1)) week + 6 day" "$date_fmt")
    # echo "\"$mon\" - \"$sun\""
    echo -e "\n\nFor week no: ${week}"
    echo -e "\t""\"$mon\" - \"$sun\""
    # echo -e "\n"
}

for z in SED
do
CW=`date '+%W'`
YR=`date '+%Y'`
MW=52
CNT=${CW}
MAX=`expr ${MW} + 1`
while [ ${CNT} -lt ${MAX} ]
do
# echo $CNT
weekof ${CNT} ${YR}
CNT=`expr ${CNT} + 1`
done
echo -e "\n"
done